int main()
{
int a=10;
switch(a)
{
case '1': // even if a=1 this case doest not work because it is checking for char '1';
printf("ONE\n");
break;
case '2':
printf("TWO\n");
break;
defa1ut:
printf("NONE\n");
}
return 0;
}
The above program compiles with out any error, but when you run it, it does not give any output
The reason is spelling of key word default is wrong.
1 comment:
I think its not a tricky Question man.....and its not as tough as u mentioned....
Post a Comment